cmjohnson
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A long read but if you can understand my reasoning, I think you'll agree with me by the end.
Here's a "pro tip" for you concerning how the neck thickness should change as you go up the neck.
It should follow the same ratio of thicknesses as the ratio of widths on the fingerboard.
So, just pulling numbers out of my head, let's imagine that the neck width changes by 10 percent from the nut to the last fret before the heel starts.
In that case, the thickness of the neck should also then change by 10 percent from the location of the nut to the start of the heel carve.
This way you retain a proportionate neck shape and the shape of the carve can remain constant. Most players will find this to be a consistently comfortable neck.
More neck and fingerboard trivia: Assuming a scale length of ABOUT 25 inches, and using a standard nut width and fingerboard taper, to wit, 1 and 11/16" width at the nut and 2.25" where the body and neck join, then if you were to put a compound radius on your fingerboard which is a 12" radius at the nut and a 16" radius at the end of the fingerboard, then you will have made a theoretically ideal fingerboard.
By theoretically ideal, I mean, visualize this: The two defined radii (12 and 16 inches) define two points on a truncated cone, 24 inches in diameter at the skinny end, 32 inches in diameter at the fatter end. (And right about 18 inches long.)
The surface of this imaginary cone is the surface of the fingerboard. If you were to extend it, to the length of the scale of the guitar, it would represent the entire string path from nut to bridge.
Following these radii, this length, and this fingerboard taper, the width of the board increases at exactly the same rate that the radius becomes flatter.
If you were to set this imaginary big fat truncated cone/barrel on its big end, on a level surface, and start drawing perfect vertical lines down it, as seen from the perspective of someone standing with the cone centered at eye level right in front of him, and you were to draw two of these vertical lines from the top of the cone to the bottom, with the lines spaced 1 and 11/16" apart at the top end, then those two lines create your perfect fingerboard.
What is interesting about this is that the edges of the fingerboard (and the frets) would be perfectly straight if you laid a straightedge across them, like if you were to string a high or low E string across them. The centerline of the fingerboard would also be a perfectly straight line according to the straightedge.
Now, if that fingerboard was NOT made with a compound radius, but only had a single radius on it (let's say 12 inches) then something interesting happens.
The center of the board remains exactly the same.
But THIS board doesn't fit into the conical profile. It's cylindrical.
And thus there is an error in the shape of the edge of the board. The board gets wider but it doesn't get flatter.
Imagine you've removed the compound radius board from our theoretical barrel, and installed the single radius board in the barrel instead. And imagine there are strings running over it.
What happened at the edges of the board? The radius doesn't get flatter toward the bottom of the barrel. If we assume that we installed this board in the barrel with the centerline of the board in exactly the same position as the original radiused board, then you will see that by comparison, the ends of the higher numbered frets are HIGHER than they would be on the surface of the barrel if the board was the original compound radiused board.
What this says is that for a single radiused board, the outer edges of the frets need to be dressed down lower than the centers of the frets. Actually the ideal line of the tops of the frets at the outer edges should be a very shallow gradual curve downward.
It is only with a compound radius board where the ratio of the radius change is the same as the ratio of the change in board width, where the ideal lines (before adding relief) made by the tops of the frets at the center and both edges of the fingerboards are exactly straight lines.
Read that paragraph again. It is vitally important to helping any builder or guitar tech to deliver consistently better fretwork with lower action. Because sometimes, straight topped fretwork is WRONG.
If the fingerboard's radius were to go too flat, too fast, then the problem is accentuated. You'd have to grind down the outer parts of the frets even more to achieve ideal action height. Imagine the board on the cone again. Flatter frets won't wrap around the barrel, they'll go straight instead and would be too high.
If the radius of the board were to get too tight, which is not something you are likely to encounter, then you'd have to grind down the middle of the frets instead.
Or, if the middle of the board was aligned to be perfect to the cone surface then the ends of the frets would just fall away too fast at the bottom of the board. They'd describe a circle INSIDE the body of the barrel. Fortunately you're not likely to encounter a compound radius board where the bottom end has a tighter radius than the nut end.
The last piece of the puzzle is the bridge saddle heights. To be ideal, they have to describe an arc that also fits perfectly into our truncated cone/barrel if it were to be extended to meet the bridge location. You can figure the desired bridge ratio by simple math, already knowing the ratios involved and the distance from nut to last fret and the scale length.
Understanding the truncated cone that defines the compound radius, and how it is natural and correct for a fingerboard that gets wider toward the bottom, will help you to deliver perfect action in guitars you make.
In simplest terms, the nut, every fret, and the bridge saddles should all be proportionate to each other and all form part of that perfect theoretical truncated cone.
Since the nut and last fret may be assumed to have 12 and 16 inch radiuses, and the span between them is about 2/3 of the way to the bridge, then you should be albe to calculate the idea bridge saddle radius now.
Answer: The bridge saddles should form about a 18" radius. A bit flatter but not much.
It's the taper of the fingerboard that dictates, even demands, that the radius of the frets should change proportionately to the fingerboard taper. That demands that the bridge saddle heights should also change according to the same proportions. And being able to visualize the truncated conical barrel is very helpful to understand why this is so.
This also indicates that if your fingerboard has a taper, then a single radius on the fingerboard is ALWAYS wrong. I was surprised when I realized this, because I've always been a fan of the 12" Gibson radius. I'd never really given much thought to it. I just like the way Gibson builds guitars. Critical thinking was not taking place.
Now I know. A tapered fingerboard (narrower at the nut end) demands a compound radius if you want potentially perfect action without having to do a lot of extra fret sculpturing.
But the compound radius has to extend to the bridge saddles, too, or it won't work perfectly.
Here's a "pro tip" for you concerning how the neck thickness should change as you go up the neck.
It should follow the same ratio of thicknesses as the ratio of widths on the fingerboard.
So, just pulling numbers out of my head, let's imagine that the neck width changes by 10 percent from the nut to the last fret before the heel starts.
In that case, the thickness of the neck should also then change by 10 percent from the location of the nut to the start of the heel carve.
This way you retain a proportionate neck shape and the shape of the carve can remain constant. Most players will find this to be a consistently comfortable neck.
More neck and fingerboard trivia: Assuming a scale length of ABOUT 25 inches, and using a standard nut width and fingerboard taper, to wit, 1 and 11/16" width at the nut and 2.25" where the body and neck join, then if you were to put a compound radius on your fingerboard which is a 12" radius at the nut and a 16" radius at the end of the fingerboard, then you will have made a theoretically ideal fingerboard.
By theoretically ideal, I mean, visualize this: The two defined radii (12 and 16 inches) define two points on a truncated cone, 24 inches in diameter at the skinny end, 32 inches in diameter at the fatter end. (And right about 18 inches long.)
The surface of this imaginary cone is the surface of the fingerboard. If you were to extend it, to the length of the scale of the guitar, it would represent the entire string path from nut to bridge.
Following these radii, this length, and this fingerboard taper, the width of the board increases at exactly the same rate that the radius becomes flatter.
If you were to set this imaginary big fat truncated cone/barrel on its big end, on a level surface, and start drawing perfect vertical lines down it, as seen from the perspective of someone standing with the cone centered at eye level right in front of him, and you were to draw two of these vertical lines from the top of the cone to the bottom, with the lines spaced 1 and 11/16" apart at the top end, then those two lines create your perfect fingerboard.
What is interesting about this is that the edges of the fingerboard (and the frets) would be perfectly straight if you laid a straightedge across them, like if you were to string a high or low E string across them. The centerline of the fingerboard would also be a perfectly straight line according to the straightedge.
Now, if that fingerboard was NOT made with a compound radius, but only had a single radius on it (let's say 12 inches) then something interesting happens.
The center of the board remains exactly the same.
But THIS board doesn't fit into the conical profile. It's cylindrical.
And thus there is an error in the shape of the edge of the board. The board gets wider but it doesn't get flatter.
Imagine you've removed the compound radius board from our theoretical barrel, and installed the single radius board in the barrel instead. And imagine there are strings running over it.
What happened at the edges of the board? The radius doesn't get flatter toward the bottom of the barrel. If we assume that we installed this board in the barrel with the centerline of the board in exactly the same position as the original radiused board, then you will see that by comparison, the ends of the higher numbered frets are HIGHER than they would be on the surface of the barrel if the board was the original compound radiused board.
What this says is that for a single radiused board, the outer edges of the frets need to be dressed down lower than the centers of the frets. Actually the ideal line of the tops of the frets at the outer edges should be a very shallow gradual curve downward.
It is only with a compound radius board where the ratio of the radius change is the same as the ratio of the change in board width, where the ideal lines (before adding relief) made by the tops of the frets at the center and both edges of the fingerboards are exactly straight lines.
Read that paragraph again. It is vitally important to helping any builder or guitar tech to deliver consistently better fretwork with lower action. Because sometimes, straight topped fretwork is WRONG.
If the fingerboard's radius were to go too flat, too fast, then the problem is accentuated. You'd have to grind down the outer parts of the frets even more to achieve ideal action height. Imagine the board on the cone again. Flatter frets won't wrap around the barrel, they'll go straight instead and would be too high.
If the radius of the board were to get too tight, which is not something you are likely to encounter, then you'd have to grind down the middle of the frets instead.
Or, if the middle of the board was aligned to be perfect to the cone surface then the ends of the frets would just fall away too fast at the bottom of the board. They'd describe a circle INSIDE the body of the barrel. Fortunately you're not likely to encounter a compound radius board where the bottom end has a tighter radius than the nut end.
The last piece of the puzzle is the bridge saddle heights. To be ideal, they have to describe an arc that also fits perfectly into our truncated cone/barrel if it were to be extended to meet the bridge location. You can figure the desired bridge ratio by simple math, already knowing the ratios involved and the distance from nut to last fret and the scale length.
Understanding the truncated cone that defines the compound radius, and how it is natural and correct for a fingerboard that gets wider toward the bottom, will help you to deliver perfect action in guitars you make.
In simplest terms, the nut, every fret, and the bridge saddles should all be proportionate to each other and all form part of that perfect theoretical truncated cone.
Since the nut and last fret may be assumed to have 12 and 16 inch radiuses, and the span between them is about 2/3 of the way to the bridge, then you should be albe to calculate the idea bridge saddle radius now.
Answer: The bridge saddles should form about a 18" radius. A bit flatter but not much.
It's the taper of the fingerboard that dictates, even demands, that the radius of the frets should change proportionately to the fingerboard taper. That demands that the bridge saddle heights should also change according to the same proportions. And being able to visualize the truncated conical barrel is very helpful to understand why this is so.
This also indicates that if your fingerboard has a taper, then a single radius on the fingerboard is ALWAYS wrong. I was surprised when I realized this, because I've always been a fan of the 12" Gibson radius. I'd never really given much thought to it. I just like the way Gibson builds guitars. Critical thinking was not taking place.
Now I know. A tapered fingerboard (narrower at the nut end) demands a compound radius if you want potentially perfect action without having to do a lot of extra fret sculpturing.
But the compound radius has to extend to the bridge saddles, too, or it won't work perfectly.