Maybe if I provide more information you'll understand that there is no contradiction. If the difference between two pickups is Q factor related, you simply adjust the pot values used in the wiring of the guitar to increase or decrease the load upon the pickup. For anyone who doesn't know, the Q factor is the degree of LC resonance, and LC resonance is where you get a spike in treble output at a particular frequency. Strat bridge pickups are known for having a high Q factor. Even the tone knob itself, near the top portion of the sweep, primarily only serves to reduce the Q. It's not until you get near the bottom of the tone dial that the capacitor has a distinctive influence. The inherent cause of different Q factors is related to the steel parts in the pickup and the eddy currents they cause. Altering the load can "put back" whatever the eddy currents have "taken away". If the difference is related to magnetic strength, you can raise or lower the pickups, or even perform a magnet swap. OTOH the other hand if a pickup has a given inductance and capacitance, the only way to move resonant peak around is with parallel capacitance or inductance, and those have drawbacks. You can move the resonance peak lower with capacitance, but since the inductance and wind count(s) is the same, the voltage wont increase as it would with a hotter wound pickup. You can raise the peak with parallel inductance, but because pickups already have such a high inductance, you need a very high value inductor in order to prevent the overall inductance from becoming extremely low. Bill Lawrence's website still offers a small inductor called a Q filter that supposedly works well, but otherwise it's not something that is as readily available as a capacitor.